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Author Topic: A question  (Read 7728 times)
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« on: August 01, 2009, 11:14:02 AM »

"We can easily check that the limit as x approaches 3 from the right and from the left is equal to 4. Hence, the limit as x approaches 3 exists, and therefore the function has a removable discontinuity at x = 3. If we define k(3) = 4 instead of k(3) = 1 then the function in fact will be continuous on the real line."

I think from the left is eqal to 6 not to 4. Thanks.

I love your real analysis website.
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« Reply #1 on: August 03, 2009, 11:34:59 AM »

Saying "you can easily check" does not guaranty that it is right - you are correct, the limit (from the left and from the right) is of course 6, not 4, and on top of it the picture is wrong, too. I'll fix it as soon as I have a chance, thanks for pointing it out. - (fixed!)
« Last Edit: November 02, 2009, 06:04:19 PM by webmaster » Logged
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