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Computer Science / Robotics Forum / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:37:49 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
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2

Computer Science / Java Forum / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:37:10 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
We are reviewing the situation to try to find a way to block unwelcome posts without blocking new registrations entirely, but no resolution deadline has been set. Very sorry for any inconvenience!



3

Mathematics / Statistics Forum / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:35:46 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
We are reviewing the situation to try to find a way to block unwelcome posts without blocking new registrations entirely, but no resolution deadline has been set. Very sorry for any inconvenience!



4

Mathematics / Complex Analysis Forum / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:35:18 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
We are reviewing the situation to try to find a way to block unwelcome posts without blocking new registrations entirely, but no resolution deadline has been set. Very sorry for any inconvenience!



5

Mathematics / Real Analysis Forum / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:34:45 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
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6

General Category / General Discussion / SelfRegistration disabled because of Spam

on: March 17, 2010, 06:32:45 PM

Selfregistration for this board has been disabled; we have had too many registrations by spammers who posted questionable, irrelevant, and frequently offensive content. If you are not currently a member and would like to post a question, please do so via email.
We are reviewing the situation to try to find a way to block unwelcome posts without blocking new registrations entirely, but no resolution deadline has been set. Very sorry for any inconvenience!



8

Mathematics / Real Analysis Forum / Re: An elusive sequence...

on: February 21, 2010, 12:08:03 PM

Perhaps it is not that bad. A sequence just means it must be a countable set so you are looking for a countable set that is 'dense', or in simpler terms kind of 'everywhere'. That might be a well known set, and since it is countable you can think of it as a sequence. If you find that set/sequence the rest might might not be too bad. Good luck!



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Mathematics / Real Analysis Forum / Re: how to prove the absolute value of any continuous function is continuous.

on: November 09, 2009, 09:41:44 AM

I would go about it using the definition of absolute value, together with the fact that f(x) is continuous. Something like this:
Recall f(x) = f(x) if f(x) >= 0 or f(x) if f(x) < 0
By assumption f(x) is continuous at c, i.e. f(x)  f(c) < epsi if x  c < delta
You need to show that  f(x)  f(c)  < epsi if x  c < delta
Now try three cases:
(1) f(c) > 0, which also implies that f(x) > 0 if x and c are close enough (why?) ... (use def of f(x)) (2) f(c) < 0, which also implies that f(x) < 0 if x and c are close enough (why?) ... (use def of f(x) again but factor out a minus sign ...) (3) f(c) = 0, which follows right away from f being continuous
Hope it helps, best of luck.



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Mathematics / Real Analysis Forum / Re: Do you want minor edits

on: October 30, 2009, 03:38:43 PM

It depends. If it's a minor typo, it will take until the next bigger problem s discovered. If it's a typo that makes the proof or statement noncomprehensible, I'll fix it quickly. If it's bigger problem, it might again take longer to fix, as more than one thing might depend on the one change. If you need something fixed urgently, let me know and I'll try my best.



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Mathematics / Real Analysis Forum / Re: A question

on: August 03, 2009, 11:34:59 AM

Saying "you can easily check" does not guaranty that it is right  you are correct, the limit (from the left and from the right) is of course 6, not 4, and on top of it the picture is wrong, too. I'll fix it as soon as I have a chance, thanks for pointing it out.  (fixed!)



